Dancing Graphs

Today I was tired again and not feeling mathematically creative, so I worked on exercises in the review of trigonometry rather than doing more work on the parabola problem. A few of the exercises involved graphing trigonometric functions. I’ve always found something enchanting in the graphs of sine and cosine, especially when they dance together as shown below.

Simultaneous Sine And Cosine

I’ve also always wondered if there is a name for the leaf-like shape formed between them

Shape Between

(And while we’re on the subject, check out this lovely animation I found of sine and cosine graphed side by side.)

Sine And Cosine

Source

Rubber Ball

I was still very tired for most of today, but I rallied in the late afternoon and managed to do 90 minutes of trig review and 30 of investigation into the parabola problem. I think I’m making progress, though I haven’t started trying to work out all the algebra and trig yet.

I will probably need some inverse trigonometric identities. I was not certain such things existed, but apparently they do. Most of the exercises I did today concerned the regular kind: either proving them or using them to turn one expression into another. I remember doing a lot of the latter kind of problem in my tenth-grade precalculus class. I always thought they were kind of fun.

Extra Extra

Sometimes, during my review, my mind will supply facts before they are mentioned or even in contexts where they never are mentioned. Other times, I will read something an think, “Wait, did I ever know that?”

Today I read about trigonometry, both in the appendix to my calculus text and in the OpenStax free textbook Algebra and Trigonometry. It turns out that, when an angle’s vertex is located at the center of a circle, the measure of that angle in radians is the ratio between the length of the arc subtended by the angle and the radius of the circle. That’s not just a property of radians; that’s what a radian is. Surely I must have known that at some point, but it came as total news to me.

Radians 1

(I’m feeling better today, though still not very good. The fun math revelations were helpful. All that I did remember about radians now makes a lot more sense.)

Conic Completion Day

Today I worked through poor concentration to finish the exercises from the review of conics. There wasn’t much left to do, in fact, because the five final exercises all called for tools from calculus that I have not reviewed yet.

Next up will be trigonometry. I didn’t start reading the appendix on that topic today, but I looked over it. I also did a little review of the Unit Circle (which, oddly, isn’t pictured in the review of trigonometry). I remember Mike, my high school math teacher for two out of three years, was very strong on the Unit Circle. He used to say that if he ever met us again as adults, his first question would be, “What’s $\sin\left(\frac{\pi}{6}\right)$?” I did remember the answer to that before my review today, so perhaps threatening years-late pop quizzes is an effective teaching technique.


I reckon it’s about time I present my hand-waving argument that repeating decimals must represent rational numbers. I proved the converse in my post Rational-a-Rama with what I think most of my audience found a boring amount of rigor. Here I’m going to err far on the other side.

Consider the repeating decimal $x=0.\overline{142857}$.

Since $x$ repeats every six digits, multiplying $x$ by $10^6$ will yield another number with the same decimal part: $10^6x=142857.\overline{142857}$

Observe that $10^6x-x=142857.\overline{142857}-0.\overline{142857}=142857$.

Thus $(10^6-1)x=142857$ and $x=\frac{142857}{10^6-1}=\frac{142857}{999999}\text{.}$

Both $142857$ and $999999$ are integers, so it follows that $x=0.\overline{142857}$ is rational.

(In fact, $x=0.\overline{142857}=\frac{142857}{999999}=\frac{1}{7}$.)

A similar argument can be made about any repeating decimal, so any repeating decimal represents a rational number.

(Note that some repeating decimals do not begin repeating right after the decimal point. An example is $y=0.58\overline{3}$ (which is $\frac{7}{12}$). Multiplying $y$ by ten and subtracting $y$ from the result yields $10y-y=5.83\overline{3}-0.58\overline{3}=5.25$. This is not an integer, but it can be made one by multiplying by 100. This leaves the equation $100(10y-y)=525$, which can be used to show that $y$ is rational in the same manner as above.)